Core practicals and skills

Units 3 and 6 are written papers that test practical skills through the 18 core practicals in the specification. This page covers the skills those papers reward (variables, data quality, uncertainty, risk and ethics), how to present data and test it with statistics, and then each core practical in turn: its aim, a short method, the variables to control, how the results are processed and the mistakes that cost marks.

How the practical units are assessed

There is no laboratory exam. Unit 3 (WBI13) at AS and Unit 6 (WBI16) at A2 are written papers, each worth 20% of its half of the course and 10% of the full International A Level. The questions are set in the context of the core practicals and of unfamiliar experiments that use the same skills: planning, identifying and controlling variables, processing data, plotting graphs, evaluating methods and drawing conclusions. Remembering the small details of a method earns only a few marks. Most marks go to explaining why each step is done and applying that reasoning to a new situation.

CPCore practicalTopicPaper
1Semi-quantitative tests for reducing sugars (Benedict's) and starch (iodine) using colour standards1Unit 3
2Vitamin C content of food and drink1Unit 3
3Membrane permeability: effect of temperature and alcohol2Unit 3
4Effect of temperature, pH, enzyme concentration and substrate concentration on the initial rate of an enzyme-catalysed reaction2Unit 3
5Light microscope drawings of animal cells; measuring with an eyepiece graticule3Unit 3
6Root tip squash to observe the stages of mitosis3Unit 3
7Plan diagrams of roots, stems and leaves; identifying sclerenchyma, phloem and xylem4Unit 3
8Tensile strength of plant fibres4Unit 3
9Antimicrobial properties of plants, with aseptic technique4Unit 3
10Rate of photosynthesis in an aquatic plant: light intensity, wavelength, temperature and carbon dioxide5Unit 6
11Ecology of a habitat: quadrats, transects and abiotic factors5Unit 6
12Effect of temperature on the development of organisms5Unit 6
13Rate of growth of microorganisms in a liquid culture6Unit 6
14Effect of different antibiotics on bacteria6Unit 6
15Respiration in yeast using an artificial hydrogen carrier (redox indicator)7Unit 6
16Simple respirometer: rate of respiration and RQ7Unit 6
17Effect of exercise on breathing, using spirometer traces7Unit 6
18Production of amylase in germinating cereal grains8Unit 6

The skills carry forward. Techniques first met at AS, such as dilutions, colorimetry, aseptic technique and measuring a rate from a graph, are used again in the A2 practicals, so the AS sections below are worth revising for Unit 6 too.

Variables and planning

An investigation asks how one factor affects another. To answer that question fairly, only one factor may change on purpose, and everything else that could affect the result must stay the same. The vocabulary below is what mark schemes look for.

Controlling variables is what makes a conclusion valid. If the temperature drifted while you changed the pH, you could not tell which factor caused the change in rate. A control experiment does a different job: it shows that the effect needs the factor at all, for example that the clearing of a milk suspension needs active enzyme and does not happen on its own.

A strong "describe how you would investigate" answer usually: names the independent variable with at least five values; says exactly how the dependent variable is measured; names two or more controlled variables and how each is kept constant; includes a control; repeats each value at least three times and calculates a mean; says how the data will be processed (graph, rate, statistical test); and gives a hazard with a precaution.

Common mistake: listing the independent or dependent variable as a controlled variable, or listing something that was not in fact kept constant. "Keep the temperature the same" earns less than "use a water bath set at 30 °C".

Quality of data

Several everyday words have exact meanings when they describe data. Use them precisely, because mark schemes reward the correct term and penalise a vague one.

Errors come in two kinds. Random errors make readings scatter unpredictably either side of the true value, for example judging the exact moment a colour disappears. Repeating and taking a mean reduces their effect. Systematic errors shift every reading by the same amount or in the same direction, for example a colorimeter that was not zeroed or a balance that was not set to zero. Repeating does not remove a systematic error; correct calibration and technique do.

Accurate andprecise Precise butnot accurate Accurate butnot precise Neither accuratenor precise
The centre of each target is the true value. A tight cluster means precise readings; a cluster centred on the bullseye means accurate ones. A systematic error produces the second pattern.

Precise does not mean accurate. Readings can agree closely with each other and still all be wrong by the same amount, if there is a systematic error such as an uncalibrated instrument.

Uncertainty and percentage error

Every reading has an uncertainty: the range within which the true value is likely to lie. For a scale it is normally taken as half the smallest division, so a thermometer marked in 1 °C steps has an uncertainty of ±0.5 °C. Glassware often has its own tolerance printed on it, and a digital display is limited by its last digit. Uncertainty is not a mistake. It remains even when the technique is perfect.

When one measurement needs two readings, such as both ends of a ruler or the start and end readings of a burette, the two uncertainties are added. A ruler read to ±0.5 mm at each end gives an overall uncertainty of ±1 mm.

percentage uncertainty = uncertainty ÷ measured value × 100

Questions often call this the percentage error. It shows how much the uncertainty matters compared with the size of the reading. Measuring 25 cm³ with a measuring cylinder read to ±0.5 cm³ gives a percentage uncertainty of 2%. Measuring only 5 cm³ with the same cylinder gives 10%: the uncertainty is the same, but the reading is smaller, so it matters more.

Repeats, anomalies and means

Taking at least three repeats at each value of the independent variable lets you calculate a mean, see how much the readings vary, and spot anomalies. Repeats make results more reliable. They do not make them more accurate, because a systematic error affects every repeat in the same way.

An anomaly is a result that does not fit the pattern: one repeat far from the others, or a point well away from the line on a graph. Typical causes include an air bubble in a cuvette, a slip in timing, or a beetroot piece that was squashed while being handled.

Give a mean to the same number of decimal places as the raw data, or one more, not to every figure on the calculator. A calculated answer should have the same number of significant figures as the least precise measurement used to work it out.

Risk assessment and safety

A hazard is anything that could cause harm, such as a corrosive acid. The risk is how likely the harm is, and how serious, in the way the procedure is actually carried out. A precaution (control measure) reduces the risk. Many practicals share the same hazards.

HazardWhere it appearsPrecaution
Warm hydrochloric acidRoot tip squash (CP6)Eye protection and gloves; warm the acid in a water bath, never over a flame
Stains: toluidine blue, acetic orcein, methylene blue, iodine; DCPIPCP1, CP2, CP5 to CP7, CP15, CP18Gloves and eye protection; they irritate and stain skin and eyes
EthanolCP3, CP9, flaming spreadersHighly flammable: no naked flames nearby; keep the ethanol beaker well away from the Bunsen burner
Scalpels, razor blades and cork borersCP3, CP6, CP7Cut on a tile, away from the body and fingers; carry blades in a tray
MicroorganismsCP9, CP13, CP14, CP18Aseptic technique; incubate at no more than 25 °C; tape lids without sealing them; never open plates after incubation; autoclave before disposal
Enzymes, especially as powdersCP4Can cause allergic reactions: avoid skin contact and do not breathe in powder
Hot water baths and boiling liquidsCP1, CP3, CP4Tongs or a test-tube holder; point tubes away from people
Falling masses and snapping fibresCP8A tray with soft padding under the masses, feet clear, eye protection
Potassium hydroxide or soda limeCP16, CP17Corrosive: gloves and goggles; keep organisms from touching it by resting them on gauze
Exercise and breathing apparatusCP17Health check first; sterilised mouthpiece; fresh soda lime; stop at once if the subject feels dizzy
FieldworkCP11Check tides and weather, work in groups, wear suitable footwear, wash hands afterwards

Exam tip: a full answer names the hazard, the harm and the precaution. "Wear eye protection because the warm hydrochloric acid could splash into the eyes" has all three parts. "Be careful with acid" has none of them.

Ethics of using living organisms

Safety is about protecting the experimenter. Ethics is about the organisms (and people) being studied. The specification names the ethical use of organisms in CP12 and CP13, so expect a mark for it there, but the same ideas apply to every practical that uses living things.

Presenting data in tables and graphs

Results tables

Temperature / °CAbsorbance, repeat 1 / AUAbsorbance, repeat 2 / AUAbsorbance, repeat 3 / AUMean absorbance / AU
200.120.100.110.11
300.150.160.140.15
400.210.190.200.20
500.330.310.62 (anomaly)0.32
600.850.880.860.86

In this beetroot example, the third reading at 50 °C is far from the other two, so it has been marked and left out of the mean (0.33 + 0.31) ÷ 2 = 0.32.

Graphs

Finding a rate from a graph

A rate is the gradient: change in y ÷ change in x, with the units of y divided by the units of x (for example cm³ s⁻¹ or AU s⁻¹). For a straight line, use a large triangle to reduce the reading uncertainty. Many biological graphs curve, because the reaction slows as the substrate is used up. For these, the initial rate is the gradient of a tangent drawn to the curve at time zero.

Time / s Product formed / AU Δx Δy tangent at t = 0 initial rate = Δy ÷ Δx rate falls as substrate is used up
Finding an initial rate. The tangent touches the curve at the origin; its gradient is the rate at the moment the reaction started.

Common mistake: using 1 ÷ time taken as "the rate". It gives only a rough average over the whole reaction, not the initial rate, and it has no proper units of amount per unit time.

Mean and standard deviation

The mean is the total divided by the number of values. The median is the middle value when they are put in order, and the mode is the most common value. The range (highest minus lowest) is a quick measure of spread, but a single anomaly changes it a lot.

The standard deviation (SD) measures how spread out the values are around the mean. The formula is given in the exam when it is needed:

s = √[ Σ(x − x̄)² ÷ (n − 1) ]

Here x is each value, x̄ is the mean and n is the number of values. A small SD means the repeats cluster closely, so they are precise and repeatable. For data that are normally distributed, about 68% of values lie within 1 SD of the mean and about 95% lie within 2 SD. When comparing two means, ranges of mean ± SD that overlap a lot suggest the difference could easily be due to chance. Ranges that do not overlap suggest a real difference, but only a statistical test can say how likely that is.

Four repeat timings agree closely: 42, 45, 44 and 43 s. Move the slider to change the fifth repeat and see what one anomaly does to the mean and the standard deviation.

Mean of all five: 43.6 s · Standard deviation: 1.1 s

With the fifth reading at 90 s, the mean moves from about 44 s to about 53 s, but the standard deviation grows nearly twenty times. That is why anomalies should be checked and, with a reason, left out before calculating.

Choosing and using a statistical test

Biological data always vary, so two means will rarely be identical and points will rarely fall on a perfect line. A statistical test decides whether a difference or a correlation is large enough that it is unlikely to be due to chance alone.

TestUse it whenExampleFormula and degrees of freedom
Student's t-testComparing the means of two sets of continuous data that are roughly normally distributedMean clear-zone diameter around garlic discs against mint discs (CP9)t = (x̄₁ − x̄₂) ÷ √(s₁²/n₁ + s₂²/n₂); degrees of freedom = n₁ + n₂ − 2
Chi-squared (χ²)Comparing observed counts in categories with the counts expected from a ratio or predictionNumbers of offspring of each phenotype against an expected 3:1 ratioχ² = Σ(O − E)² ÷ E; degrees of freedom = number of categories − 1
Spearman's rank correlationTesting for a correlation between two variables measured on the same samples (paired data), ideally at least ten pairsLight intensity and percentage cover of a plant in each quadrat (CP11)rs = 1 − 6Σd² ÷ n(n² − 1); use n, the number of pairs

Chi-squared must be done on the actual counts, never on percentages or means. The t-test needs means and standard deviations. Spearman's test uses only the ranks of the values, so it can be used on data that are not normally distributed.

What a significant result means

The 5% level is the cut-off biologists agree on. A result is significant when the calculated value reaches the critical value: there is then less than a 5% probability that a difference (or correlation) this large would arise by chance alone. You reject the null hypothesis and report a significant difference or a significant correlation. If the calculated value is below the critical value, you accept the null hypothesis, because the difference could be due to chance.

With chi-squared, a value below the critical value is often the result that was expected. For example, χ² = 2.1 with 1 degree of freedom is below the critical value of 3.84, so the observed numbers do not differ significantly from a 3:1 ratio.

A significant result supports a hypothesis; it never proves it. A significant correlation shows that two variables change together, not that one causes the other. Another factor may be changing along with both.

Worked example. Light intensity and the percentage cover of grass were recorded in ten quadrats along a belt transect from woodland into an open field.

Quadrat12345678910
Light intensity / lx21034040052068075081096010201190
Cover of grass / %514820261841353060

Null hypothesis: there is no correlation between light intensity and the percentage cover of grass.

Rank each variable separately, giving rank 1 to the smallest value. Light intensity already rises from quadrat 1 to 10, so its ranks are 1 to 10. For cover: 5% is rank 1, 8% is 2, 14% is 3, 18% is 4, 20% is 5, 26% is 6, 30% is 7, 35% is 8, 41% is 9 and 60% is 10.

If two values tie, each gets the mean of the ranks they would share, so two values in 4th and 5th place are both ranked 4.5.

For each quadrat, find the difference between the two ranks (d) and square it.

Quadrat12345678910
Rank of light12345678910
Rank of cover13256498710
d0−11−1−12−2020
d²0111144040

Σd² = 16.

rs = 1 − (6 × Σd²) ÷ n(n² − 1) = 1 − (6 × 16) ÷ (10 × 99) = 1 − 96 ÷ 990 = 1 − 0.097 = 0.903.

The critical value for 10 pairs at p = 0.05 is 0.648 (the table is given in the question). 0.903 is greater than 0.648, so the null hypothesis is rejected.

Conclusion: there is a significant positive correlation between light intensity and the percentage cover of grass. There is less than a 5% probability that a correlation this strong arose by chance.

This does not show that light causes the grass to grow better. Soil moisture or trampling may also change along the same transect, so an experiment that varies light alone would be needed to show cause.

Techniques used in several practicals

Making dilutions

To make a solution of lower concentration from a stock solution, use C₁V₁ = C₂V₂, where C₁ and V₁ are the concentration and volume of stock used and C₂ and V₂ are those of the solution being made. For 10 cm³ of 0.4% glucose from a 2% stock: V₁ = (0.4 × 10) ÷ 2 = 2 cm³ of stock, made up with 8 cm³ of distilled water.

A serial dilution repeats the same dilution step, so each solution is a fixed fraction of the one before. Adding 1 cm³ of a solution to 9 cm³ of water dilutes it tenfold, so a series gives 10⁻¹, 10⁻², 10⁻³ and so on. Serial dilutions are used to count bacteria (CP13) and to make a range of gibberellin concentrations (CP18). Mix each tube thoroughly and use a clean pipette at every step, or solution carried over will make the later tubes too concentrated.

Using a colorimeter

Aseptic technique

Aseptic technique keeps unwanted microorganisms out of cultures and keeps cultures away from people. It matters even with harmless strains: a culture can become contaminated, or a strain can mutate, so all cultures are treated as possible pathogens.

Unit 3 core practicals: Topics 1 and 2

CP1 · Reducing sugars and starch with colour standards

A qualitative test only tells you whether a substance is present. A quantitative test gives its exact amount. A semi-quantitative test sits in between: it gives a rough estimate by comparing the sample with standards of known concentration.

A test tube of sample solution, an arrow to a tube with Benedict's reagent added standing in a water bath heated from below, then an arrow to a row of five tubes coloured blue, green, yellow, orange-red and brick-red, with a scale beneath running from no reducing sugar to high concentration.
The Benedict's test as a semi-quantitative method: after heating, the colour of the tube is compared with a scale running from blue (none) to brick-red (high). The colour is only a rough guide to the concentration.

CP2 · Vitamin C content of food and drink

Vitamin C (ascorbic acid) is an antioxidant and a reducing agent. DCPIP is a blue dye that turns colourless when it is reduced. The more vitamin C a juice contains, the smaller the volume needed to decolourise a fixed volume of DCPIP.

Boiling vegetables lowers their vitamin C. The vitamin is water-soluble, so it passes out of the damaged cells into the cooking water, and heat also speeds up its breakdown.

1.0 cm³ of DCPIP was decolourised by a mean of 0.60 cm³ of a 1.0 mg cm⁻³ vitamin C standard. Mass of vitamin C needed = 0.60 × 1.0 = 0.60 mg.

The same 1.0 cm³ of DCPIP was decolourised by a mean of 1.5 cm³ of orange juice, so 1.5 cm³ of juice contains 0.60 mg of vitamin C.

Concentration in the juice = 0.60 ÷ 1.5 = 0.40 mg cm⁻³ (40 mg per 100 cm³).

Shortcut: concentration in juice = (volume of standard ÷ volume of juice) × concentration of standard = (0.60 ÷ 1.5) × 1.0.

CP3 · Membrane permeability: temperature and alcohol

Beetroot cells store a red pigment, betalain, in their vacuoles. To leak out it must cross two membranes: the tonoplast around the vacuole and the cell surface membrane. The amount of pigment in the surrounding water therefore shows how permeable those membranes have become.

At low temperatures little pigment escapes. As the temperature rises, the phospholipids move more and the bilayer becomes more fluid, so leakage creeps up. Above roughly 50 to 60 °C the membrane proteins denature and the bilayer is disrupted, leaving gaps, so leakage rises steeply. Ethanol is a lipid solvent: it disrupts the phospholipid bilayer and denatures membrane proteins, so leakage increases with ethanol concentration.

CP4 · Initial rate of an enzyme-catalysed reaction

The initial rate is used because it is the only point at which the conditions are exactly those that were set. As the reaction goes on, substrate is used up and product builds up, so the rate falls for reasons that have nothing to do with the factor being tested.

Unit 3 core practicals: Topics 3 and 4

CP5 · Animal cells and the eyepiece graticule

A Paramecium drawn above an eyepiece graticule scale numbered from 0 to 100. Dashed lines run from the two ends of the cell down to the scale at 8 and 85 units, with a double-headed arrow between them labelled 85 minus 8 equals 77 units.
Measuring with a graticule. The cell spans 85 − 8 = 77 eyepiece units; with each unit calibrated at 2.5 µm, it is 77 × 2.5 = 192.5 µm long.

CP6 · Root tip squash and the stages of mitosis

CP7 · Plant tissues: sclerenchyma, phloem and xylem

Stains are needed because thin plant sections absorb little light and look almost transparent. A stain is taken up differently by different walls, which creates contrast between tissues. Too much stain makes everything dark and hides the differences.

CP8 · Tensile strength of plant fibres

A clamp stand with a plant fibre hanging from its arm. A hook at the lower end of the fibre carries a stack of 100 gram masses, above a container lined with soft fabric standing on the bench.
Apparatus for finding the breaking mass of a fibre. The padded container under the masses stops them falling onto the bench or onto feet when the fibre snaps.

CP9 · Antimicrobial properties of plants

A closed Petri dish seen from the side, with agar in the base. Two short strips of tape on opposite sides each run from the lid down over its edge onto the base, and an arrow shows air still getting in under the lid.
A Petri dish lid held with two short strips of tape. The lid cannot be knocked off, but air can still get in, so conditions stay aerobic and anaerobic pathogens are not encouraged.

Unit 6 core practicals: Topics 5 and 6

CP10 · Rate of photosynthesis in an aquatic plant

CP11 · Ecology of a habitat

CP12 · Effect of temperature on development

CP13 · Growth of microorganisms in a liquid culture

CP14 · Effect of different antibiotics on bacteria

Unit 6 core practicals: Topics 7 and 8

CP15 · Respiration in yeast with a redox indicator

During glycolysis and the Krebs cycle, dehydrogenase enzymes remove hydrogen from respiratory substrates and pass it to NAD and FAD. An artificial hydrogen carrier (a redox indicator) added to a yeast suspension picks up some of this hydrogen and changes colour as it is reduced. Methylene blue and DCPIP turn from blue to colourless; TTC turns from colourless to red. The faster the yeast respires, the faster the colour changes.

CP16 · Respirometer: rate of respiration and RQ

scale capillary U-tube with coloured fluid syringe and three-way tap (resets the fluid) seeds rest on gauze potassium hydroxide solution absorbs CO₂ glass beads (control) germinating seeds water bath at constant temperature
A respirometer with a control tube. As the seeds take in oxygen, the carbon dioxide they give out is absorbed, so the pressure in their tube falls and the fluid rises on that side (arrow). Any change caused by temperature or air pressure affects both tubes equally and cancels out.

With potassium hydroxide present, the fluid moved 25 mm in 10 minutes in a capillary of radius 0.50 mm. Oxygen used = πr² × distance = 3.14 × 0.50² × 25 = 19.6 mm³, a rate of 1.96 mm³ min⁻¹.

The absorbent removes all the carbon dioxide released, so the only change in gas volume is the oxygen taken in.

The experiment was repeated with water in place of the absorbent. The fluid moved 7.5 mm towards the seeds in 10 minutes, a net decrease of 3.14 × 0.50² × 7.5 = 5.9 mm³.

Now the carbon dioxide given out partly replaces the oxygen taken in, so the change equals oxygen used minus carbon dioxide produced.

Carbon dioxide produced = 19.6 − 5.9 = 13.7 mm³.

RQ = CO₂ produced ÷ O₂ used = 13.7 ÷ 19.6 = 0.70, which suggests the seeds are respiring lipid, as oil-rich seeds do.

If the fluid had moved away from the seeds without absorbent, more carbon dioxide was released than oxygen used; the two volumes are then added, and the RQ is above 1.

CP17 · Exercise and spirometer traces

A spirometer has a chamber of medical-grade oxygen floating over water. As the subject breathes in and out through a mouthpiece, the chamber falls and rises, and a pen or data logger records the volume as a trace. Soda lime absorbs the carbon dioxide breathed out, so the total volume in the chamber slowly falls as oxygen is used, and the whole trace slopes downwards. The specification asks you to interpret traces; it does not require you to use a spirometer yourself.

CP18 · Amylase production in germinating cereal grains

When a cereal grain takes in water, the embryo releases gibberellin. Gibberellin diffuses to the aleurone layer and switches on transcription of the gene for amylase. The amylase digests starch in the endosperm to maltose, which the embryo uses for respiration and growth.

Quick checks

A student investigates the effect of temperature on pigment leakage from beetroot. Which of these is a controlled variable?

Surface area affects how much pigment can escape, so it must be kept the same in every tube. Temperature is the independent variable, the commonest wrong choice, and absorbance (which measures pigment concentration) is the dependent variable.

Repeat readings of 4.1, 4.2, 4.1 and 4.2 cm³ are obtained when the true value is 5.0 cm³. How would you describe these readings?

The readings agree closely with each other, so they are precise, but all are well below the true value, so they are not accurate. This pattern points to a systematic error. "Accurate but not precise" mixes the two terms up.

A volume of 20 cm³ is measured with a measuring cylinder that has an uncertainty of ±0.5 cm³. What is the percentage uncertainty?

Percentage uncertainty = 0.5 ÷ 20 × 100 = 2.5%. An answer of 0.5% just repeats the uncertainty without dividing it by the measurement.

Fifteen discs soaked in garlic extract and fifteen soaked in mint extract were tested on agar plates. Which statistical test should be used to compare the mean diameters of their clear zones?

Two means of continuous data are being compared, which is what the t-test is for. Chi-squared needs counts in categories, and Spearman's rank looks for a correlation between two paired variables, not a difference between two groups.

A Spearman's rank test on 10 pairs gives rs = 0.45. The critical value at p = 0.05 is 0.648. What should be concluded?

0.45 is below the critical value, so the null hypothesis of no correlation is accepted. A positive value alone does not make a correlation significant, and even a significant correlation would not show cause.

40 eyepiece units match 100 µm on a stage micrometer. A cell measures 18 eyepiece units with the same objective. What is its actual length?

One eyepiece unit = 100 ÷ 40 = 2.5 µm, so the cell is 18 × 2.5 = 45 µm. 7.2 µm comes from dividing the wrong way (18 × 40 ÷ 100).

Why is a root tip placed in warm hydrochloric acid when making a root tip squash?

The acid hydrolyses the pectins that hold neighbouring cells together, so the tissue can be spread into a single layer. Staining is done separately with a stain such as acetic orcein, which is the commonest confusion.

In a respirometer containing potassium hydroxide, why does the coloured fluid move towards the tube of germinating seeds?

Oxygen is removed by respiration and its replacement, carbon dioxide, is absorbed, so the pressure in the seed tube drops and the fluid is drawn towards it. Heat from the seeds would push the fluid the other way, and the control tube is there to cancel such effects.

Interactive diagrams

Drag the two means apart and watch t pass the critical value: the difference becomes significant. Then widen the standard deviations or reduce the sample size (More settings): the ±1 SD bars overlap and t falls.