Transition metals and their chemistry

Copper sulfate is blue, potassium manganate(VII) purple, and iron catalyses the Haber process. These properties all come from one feature of the transition metals: an incomplete set of d electrons. This topic explains complex ions, their shapes and colours, the many oxidation states of vanadium and chromium, the reactions of metal aqua ions, and how transition metals act as catalysts.

What makes a transition metal

A transition metal is a d-block element that forms one or more stable ions with an incomplete d sub-shell. Across the period from scandium to zinc, electrons are added to the 3d sub-shell, but when the atoms form ions they lose their 4s electrons first.

ElementAtomCommon ionIon configuration
Ti[Ar] 3d2 4s2Ti3+[Ar] 3d1
Cr[Ar] 3d5 4s1Cr3+[Ar] 3d3
Fe[Ar] 3d6 4s2Fe2+, Fe3+[Ar] 3d6, [Ar] 3d5
Cu[Ar] 3d10 4s1Cu2+[Ar] 3d9

Complex ions and ligands

Shapes of complex ions

ShapeCoordination numberBond angleExamples
octahedral690°[Cu(H2O)6]2+, [Ni(NH3)6]2+; most complexes with small ligands
tetrahedral4109.5°[CuCl4]2−, [CoCl4]2−: chloride ions are larger, so fewer fit around the metal
square planar490°cisplatin, [Pt(NH3)2Cl2]
linear2180°[Ag(NH3)2]+ (in Tollens' reagent), [Ag(S2O3)2]3−, [Ag(CN)2]−

Cisplatin and haemoglobin

Cisplatin is a square planar platinum(II) complex with the two ammonia ligands next to each other (cis) and the two chloride ligands next to each other. Its isomer with them opposite each other, transplatin, has no anticancer action. In the body a chloride ligand is replaced by water, [Pt(NH3)2Cl2] + H2O → [Pt(NH3)2Cl(H2O)]+ + Cl−, and the platinum then forms dative bonds to nitrogen atoms on neighbouring bases in DNA, kinking the strand so the cancer cell cannot copy its DNA and divide. It also binds to the DNA of healthy cells, which causes side effects such as hair loss.

Haemoglobin carries oxygen as a ligand bonded to Fe2+ in haem. Carbon monoxide is toxic because it forms a much stronger dative bond to the iron, replacing oxygen in a ligand exchange that is hard to reverse, so less oxygen can be carried.

Why transition metal compounds are coloured

In an isolated ion the five 3d orbitals have the same energy. When ligands bond to the ion, their lone pairs repel the d electrons, and in an octahedral complex the d orbitals split into two groups at different energies, separated by ΔE. A d electron can absorb a photon of visible light whose energy exactly matches ΔE and jump to the upper group:

\[ \Delta E = hf \]

The light that is absorbed is removed from white light, and the colour we see is the complementary colour of the light that is transmitted or reflected. Hydrated copper(II) ions absorb in the orange-red region, so they look blue.

Measuring concentration by colorimetry

The amount of light a coloured solution absorbs is proportional to the concentration of the coloured species. A colorimeter (spectrophotometer) uses a filter of the complementary colour, the colour the solution absorbs most strongly. If a complex is only pale, first add a ligand that forms a more intensely coloured complex. Make up solutions of known concentration, measure their absorbance, and plot a calibration curve; then measure the unknown and read its concentration from the graph.

Variable oxidation states

The 4s and 3d electrons are similar in energy, so transition metals can lose different numbers of them. Some general trends: high oxidation states such as manganese(VII) in MnO4− are oxidising agents; low ones such as V2+ and Fe2+ are reducing agents; and the +2 state becomes more stable relative to +3 across the period.

Vanadium

Oxidation stateIonColour in solution
+5VO2+ (from ammonium vanadate(V), NH4VO3, in acid)yellow
+4VO2+blue
+3V3+green
+2V2+violet

Adding zinc to acidified vanadate(V) reduces it step by step, through yellow, then green (a mixture of yellow and blue), blue, green and finally violet. Electrode potentials explain how far a reducing agent can go:

Chromium

Start with the change: [Cr(OH)6]3− → CrO42−.

Balance oxygen with water and hydrogen with H+, as if in acid: [Cr(OH)6]3− → CrO42− + 2H2O + 2H+.

Balance charge with electrons: [Cr(OH)6]3− → CrO42− + 2H2O + 2H+ + 3e−.

Add OH− to both sides to turn each H+ into water: [Cr(OH)6]3− + 2OH− → CrO42− + 4H2O + 3e−.

Reactions of metal aqua ions

A Lewis acid accepts an electron pair; a Lewis base donates one. In a complex the ligands are Lewis bases and the metal ion is a Lewis acid. Dissolved transition metal salts form hexaaqua ions, [M(H2O)6]2+ or [M(H2O)6]3+.

Acidity of aqua ions

The metal ion pulls electron density from the oxygen of each water ligand, weakening its O–H bonds, so a proton can be lost to the solvent:

[Fe(H2O)6]3+ + H2O ⇌ [Fe(H2O)5(OH)]2+ + H3O+

3+ ions are smaller and more highly charged than 2+ ions, so they have a greater charge density and polarise the water ligands more strongly. Solutions of M3+ ions are therefore noticeably acidic (around pH 2 to 3), while M2+ solutions are only very weakly acidic. This hydrolysis is why iron(III) solutions look yellow-brown rather than pale violet.

Deprotonation: hydroxide precipitates

Hydroxide ions and ammonia act as Brønsted–Lowry bases, removing protons from water ligands one at a time until a neutral complex forms, which precipitates:

Amphoteric hydroxides

The hydroxides of chromium(III) and zinc dissolve in excess sodium hydroxide, because further deprotonation gives a soluble negative ion; they also dissolve in acid. A hydroxide that reacts with both acids and alkalis is amphoteric:

Ligand exchange

Stability of complexes and the chelate effect

Replacing monodentate ligands with bidentate or multidentate ones gives a much more stable complex. This chelate effect is explained by entropy:

Working out formulae with silver nitrate

Chloride can be a ligand bonded to the metal or a free ion outside the complex. Silver nitrate precipitates only the free chloride ions as AgCl, so the mole ratio shows how many are outside. The three isomers of formula CrCl3·6H2O behave differently:

ComplexMol AgCl per molColour
[Cr(H2O)6]Cl33violet
[Cr(H2O)5Cl]Cl2·H2O2pale green
[Cr(H2O)4Cl2]Cl·2H2O1dark green

Transition metals as catalysts

A catalyst speeds up a reaction by providing an alternative route with a lower activation energy, and is unchanged at the end. Transition metals are good catalysts because they can change oxidation state easily, and because they can use their 3d and 4s electrons to form weak bonds to reactants on their surface.

Heterogeneous catalysis

A heterogeneous catalyst is in a different phase from the reactants, usually a solid with gases or liquids. The reaction happens on its surface:

  1. Reactant molecules are adsorbed onto active sites on the surface, forming weak bonds to the metal.
  2. Bonds within the reactants are weakened, and the molecules are held close together in a favourable orientation, so they react more easily.
  3. The products are desorbed from the surface, freeing the sites.

Homogeneous catalysis

A homogeneous catalyst is in the same phase as the reactants. It works by forming an intermediate, usually by changing oxidation state and then changing back.

Overall: S2O82− + 2I− → 2SO42− + I2. Uncatalysed it is slow, because two negative ions repel each other, so collisions with enough energy are rare.

Step 1: 2Fe2+ + S2O82− → 2Fe3+ + 2SO42−

Step 2: 2Fe3+ + 2I− → 2Fe2+ + I2. The iron is back as Fe2+, and Fe3+ works equally well because the steps can happen in either order.

Both steps are between oppositely charged ions, so they are faster. This works because E⦵(Fe3+/Fe2+) = +0.77 V lies between E⦵(I2/I−) = +0.54 V and E⦵(S2O82−/SO42−) = +2.01 V, so both steps are feasible.

Electrode potentials show that a catalyst could work, but not that it will speed the reaction up: they say nothing about rates.

Autocatalysis

In autocatalysis a product catalyses the reaction. In the titration of ethanedioate with manganate(VII), 2MnO4− + 16H+ + 5C2O42− → 2Mn2+ + 10CO2 + 8H2O, the reaction starts slowly (again two negative ions must collide), then speeds up as Mn2+ builds up, because Mn2+ provides a faster route:

Quick checks

What is the electron configuration of Fe3+?

Iron is [Ar] 3d6 4s2; the two 4s electrons are lost first, then one 3d electron.

What is the coordination number of chromium in [Cr(C2O4)3]3−?

Each ethanedioate is bidentate, forming two dative bonds: 3 × 2 = 6. The coordination number counts bonds, not ligands.

Why is a solution of [Zn(H2O)6]2+ colourless?

Zn2+ is 3d10. With every d orbital full, an electron cannot move to the upper set, so no visible light is absorbed.

Excess aqueous ammonia is added to aqueous copper(II) sulfate. What is seen?

A little ammonia deprotonates the aqua ion, giving blue [Cu(OH)2(H2O)4]; excess ammonia then exchanges ligands to form deep blue [Cu(NH3)4(H2O)2]2+.

Why are solutions of [Fe(H2O)6]3+ more acidic than those of [Fe(H2O)6]2+?

Both have six water ligands. The smaller, more highly charged Fe3+ ion polarises them more, so they release H+ more readily.

Which reaction is favoured mainly by a large increase in entropy?

Four particles become seven when bidentate en replaces ammonia: the chelate effect. ΔH is close to zero because Ni–N bonds are broken and made.

Zinc and acid reduce vanadium(V) to vanadium(II), but tin only reduces it to vanadium(III). Why?

Sn2+/Sn is −0.14 V. It can reduce couples with more positive E⦵ (+1.00 and +0.34 V) but not V3+/V2+ at −0.26 V. Zinc, at −0.76 V, can reduce all three.

In heterogeneous catalysis, why is silver a poor catalyst for many reactions?

Too weak adsorption (silver) and too strong adsorption (tungsten) both make poor catalysts. Nickel and platinum adsorb with intermediate strength.

Interactive diagrams

Choose a complex ion, then drag the wavelength slider. The electron absorbs the photon whose energy matches ΔE, so the solution shows the complementary colour.
Choose a metal aqua ion and a reagent to see the observation, the product and the equation. Compare a few drops with excess, and sodium hydroxide with ammonia.
Tick Add Mn2+ at the start and compare the two curves. With none added the curve starts flat, then plunges as the product catalyses the reaction; with it added there is no slow start.