Organic synthesis

This topic pulls the organic chemistry of the course together. It shows how to plan a route from one compound to another, how to lengthen a carbon chain with Grignard reagents, and the practical techniques used to make, separate, purify and identify an organic product safely.

Planning a synthetic route

To plan a synthesis, identify the functional group you start with and the one you need, then work out a sequence of known reactions that connects them, often working backwards from the target. For each step you must be able to give the reagents, the conditions and the type of reaction. Fewer steps usually means a higher overall yield, because some product is lost at every stage.

Key aliphatic conversions

From → toReagents and conditionsType of reaction
alkane → halogenoalkaneCl2 or Br2, UV lightfree-radical substitution
alkene → alkaneH2, nickel catalyst, heataddition (reduction)
alkene → halogenoalkane / dihalogenoalkaneHBr or Br2, room temperatureelectrophilic addition
alkene → alcoholsteam, phosphoric(V) acid catalyst, high temperature and pressurehydration (addition)
alkene → diolacidified potassium manganate(VII)oxidation
halogenoalkane → alcoholaqueous NaOH or KOH, heat under refluxnucleophilic substitution
halogenoalkane → alkeneKOH in ethanol, heat under refluxelimination
halogenoalkane → nitrileKCN in aqueous ethanol, heat under refluxnucleophilic substitution (adds one carbon)
halogenoalkane → amineexcess ammonia in ethanol, heat in a sealed tubenucleophilic substitution
alcohol → halogenoalkanePCl5; or KBr with 50% H2SO4; or red phosphorus and iodinesubstitution
alcohol → alkeneconcentrated H3PO4 (or H2SO4), heatelimination (dehydration)
primary alcohol → aldehydeK2Cr2O7 and dilute H2SO4, heat gently and distil off the aldehyde as it formsoxidation
primary alcohol or aldehyde → carboxylic acidexcess K2Cr2O7 and dilute H2SO4, heat under refluxoxidation
secondary alcohol → ketoneK2Cr2O7 and dilute H2SO4, heat under refluxoxidation
aldehyde, ketone or carboxylic acid → alcoholLiAlH4 in dry etherreduction
aldehyde or ketone → hydroxynitrileHCN with KCNnucleophilic addition (adds one carbon)
nitrile → carboxylic aciddilute HCl, heat under refluxhydrolysis
nitrile → amineLiAlH4 in dry ether, or H2 with a nickel catalystreduction
carboxylic acid → acyl chloridePCl5, room temperaturesubstitution
carboxylic acid → esteralcohol with concentrated H2SO4, heatesterification (condensation)
acyl chloride → acid / ester / amide / N-substituted amidewater / alcohol / concentrated ammonia / primary amine, all at room temperatureaddition–elimination
ester → carboxylic acid (or its salt) + alcoholdilute acid or aqueous NaOH, heat under refluxhydrolysis

Aromatic routes

Grignard reagents

A Grignard reagent, RMgX, is made by warming a halogenoalkane with magnesium turnings in dry ether: CH3CH2Br + Mg → CH3CH2MgBr (ethylmagnesium bromide). The carbon bonded to magnesium carries a partial negative charge, so it acts as a nucleophilic carbon and forms new carbon–carbon bonds, lengthening the chain. Everything must be dry, because water destroys the reagent.

The Grignard reagent adds to the δ+ carbon of a C=O group; adding water (or dilute acid) afterwards gives the product.

Grignard reagent reacts withProduct (after adding water)Example with CH3CH2MgBr
methanal, HCHOprimary alcoholCH3CH2CH2OH, propan-1-ol
another aldehyde, R′CHOsecondary alcoholwith ethanal: CH3CH2CH(OH)CH3, butan-2-ol
a ketone, R′COR″tertiary alcoholwith propanone: CH3CH2C(OH)(CH3)2, 2-methylbutan-2-ol
carbon dioxidecarboxylic acidCH3CH2COOH, propanoic acid

The general equations, with the magnesium ending up as Mg(OH)X: RMgX + HCHO → RCH2OH; RMgX + R′CHO → RCH(OH)R′; RMgX + R′COR″ → RR′C(OH)R″; RMgX + CO2 → RCOOH (each after adding H2O). Other ways to add a carbon are reacting a halogenoalkane with KCN, or a carbonyl with HCN.

Practical techniques

Heating under reflux and distillation

Purifying an organic liquid

  1. Put the impure product in a separating funnel and shake it with sodium hydrogencarbonate solution to neutralise acid impurities, releasing the pressure of CO2 often. Shaking with saturated sodium chloride solution helps the layers separate.
  2. Let the layers separate and run off the aqueous layer. The organic layer is usually the less dense, upper layer, but check densities.
  3. Run the organic layer into a dry flask and add a drying agent, such as anhydrous calcium chloride or magnesium sulfate, until the liquid is clear. The drying agent must be insoluble in, and not react with, the product.
  4. Decant or filter the liquid off the drying agent and distil, collecting the fraction at the product's boiling point.

Purifying an organic solid: recrystallisation

StepReason
Dissolve the impure solid in the minimum volume of hot solvent.The solvent should dissolve the compound well when hot but poorly when cold. Using the minimum gives a saturated solution, so crystals form on cooling.
Filter the hot solution quickly through a fluted filter paper.Removes insoluble impurities; keeping it hot stops crystals forming in the funnel.
Cool the filtrate, finally in ice.The compound crystallises; soluble impurities stay dissolved because there is too little of them to saturate the solution.
Collect the crystals by suction filtration with a Büchner funnel.Reduced pressure makes filtration fast.
Wash with a little cold solvent and dry between filter papers.Removes soluble impurities on the surface without dissolving much product. Wet crystals give a mass that is too high, even a "yield" above 100%.

Steam distillation and solvent extraction

Checking purity

Hazards and risks

Identifying the product

Combustion analysis

0.290 g of a compound of C, H and O burns completely to give 0.660 g of CO2 and 0.270 g of H2O. Find its empirical formula.

Carbon: moles of CO2 = 0.660 ÷ 44.0 = 0.0150 mol, so 0.0150 mol of C, mass 0.180 g.

Hydrogen: moles of H2O = 0.270 ÷ 18.0 = 0.0150 mol, so 2 × 0.0150 = 0.0300 mol of H, mass 0.030 g.

Oxygen by difference: 0.290 − 0.180 − 0.030 = 0.080 g, so 0.080 ÷ 16.0 = 0.0050 mol.

Ratio C : H : O = 0.0150 : 0.0300 : 0.0050 = 3 : 6 : 1, so the empirical formula is C3H6O. If the mass spectrum shows M+ at 58, this is also the molecular formula: propanone or propanal, which IR, NMR or chemical tests can tell apart.

The spectroscopic methods (mass spectra, IR and NMR) are covered in Topics 10 and 15, including a full worked identification.

Chemical tests for functional groups

Functional groupTestPositive result
alkenebromine waterorange to colourless
alcohol or carboxylic acid (–OH)PCl5steamy fumes of HCl
alcohol, phenol or carboxylic acidsodium metalfizzing (hydrogen)
aldehyde or ketone2,4-DNPHorange precipitate
aldehydeFehling's or Benedict's solution, warmblue to brick-red precipitate
aldehydeTollens' reagent, warmsilver mirror
CH3CO– or CH3CH(OH)–iodine and NaOH, warmpale yellow precipitate of CHI3
carboxylic acidsodium carbonate or hydrogencarbonatefizzing (CO2)
primary or secondary alcohol, aldehydeacidified K2Cr2O7, warmorange to green
halogenoalkanewarm with NaOH(aq), acidify with HNO3, add AgNO3white (Cl), cream (Br) or yellow (I) precipitate, forming slowly
acyl chloridewater, then AgNO3steamy fumes, then an immediate white precipitate

Quick checks

Which sequence converts bromoethane into propanoic acid?

Cyanide adds a carbon (CH3CH2CN), and acid hydrolysis turns the nitrile into CH3CH2COOH. NaOH then oxidation would give ethanoic acid, with only two carbons.

Which product forms when CH3MgI reacts with propanone and the mixture is then treated with water?

A Grignard reagent with a ketone gives a tertiary alcohol: the CH3 joins the carbonyl carbon, giving (CH3)3COH.

Why is a primary alcohol oxidised under reflux to make a carboxylic acid, but distilled to make an aldehyde?

The aldehyde has a lower boiling point than the alcohol and acid, so distillation carries it away before it meets more oxidising agent.

In recrystallisation, why is the minimum volume of hot solvent used?

With too much solvent, much of the product stays dissolved when cold and the yield falls, or no crystals form at all.

A student's crystals melt between 118 °C and 124 °C; the data book value is 127 °C. What does this suggest?

A pure substance melts sharply at its data book value. A low, broad melting range points to impurities, such as remaining solvent.

Which statement about hazard and risk is correct?

A hazard is the potential to cause harm; risk is the chance that harm actually happens, which falls with smaller amounts, lower concentrations and good control measures.

Interactive diagrams

Pick a starting functional group and a target, such as halogenoalkane to carboxylic acid. The shortest route is highlighted on the map, with the reagents, conditions and reaction type for every step.
Pick a Grignard reagent and a compound for it to react with. Look for the new carbon–carbon bond (red) and the kind of product it gives.